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Extending the namespace std

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Contents

[edit] Adding declarations to std

It is undefined behavior to add declarations or definitions to namespace std or to any namespace nested within std, with a few exceptions noted below

#include <utility>
namespace std {
    // a function definition added to namespace std: undefined behavior
    pair<int, int> operator+(pair<int, int> a, pair<int, int> b) {
        return {a.first+b.first, a.second+b.second};
    }
}

[edit] Adding template specializations

It is allowed to add template specializations for any standard library class (since C++20)template to the namespace std only if the declaration depends on at least one program-defined type and the specialization satisfies all requirements for the original template, except where such specializations are prohibited.

// Get the declaration of the primary std::hash template.
// We are not permitted to declare it ourselves.
// <typeindex> is guaranteed to provide such a declaration, 
// and is much cheaper to include than <functional>.
 
#include <typeindex> 
 
// Specialize std::hash so that MyType can be used as a key in 
// std::unordered_set and std::unordered_map
namespace std {
    template <> struct hash<MyType> {
      std::size_t operator()(const MyType& t) const { return t.hash(); }
    };
}
  • It is undefined behavior to declare a full specialization of any member function of a standard library class template
  • It is undefined behavior to declare a full specialization of any member function template of a standard library class or class template
  • It is undefined behavior to declare a full or partial specialization of any member class template of a standard library class or class template.
  • It is undefined behavior to declare a full or partial specialization of any standard library variable template.
  • Specializing the template std::complex for any type other than float, double, and long double is unspecified.
  • Specializations of std::hash for program-defined types must satisfy Hash requirements.
  • Specializations of std::atomic must have a deleted copy constructor, a deleted copy assignment operator, and a constexpr value constructor.
  • Specializations of std::istreambuf_iterator must have a trivial copy constructor, a constexpr default constructor, and a trivial destructor.
(until C++17)

[edit] Explicit instantiation of templates

It is allowed to explicitly instantiate a class (since C++20)template defined in the standard library only if the declaration depends on the name of at least one program-defined type and the instantiation meets the standard library requirements for the original template.

[edit] Other restrictions

The namespace std may not be declared as an inline namespace.

[edit] Addressable functions

The behavior of a C++ program is unspecified (possibly ill-formed) if it explicitly or implicitly attempts to form a pointer, reference (for free functions and static member functions) or pointer-to-member (for non-static member functions) to the a standard library function or an instantiation of a standard library function template, unless it is designated an addressable function.

The only addressable functions in the standard library are I/O manipulators that are functions (or instantiations of function templates) taking a reference to a stream as their only argument, e.g. std::endl, std::boolalpha.

Following code was well-defined in C++17, but leads to unspecified behaviors and possibly fails to compile since C++20:

#include <cmath>
#include <memory>
int main()
{
    auto fptr0 = &std::betaf; // by unary operator&
    auto fptr1 = std::addressof(std::betal) // by std::addressof
    auto fptr2 = std::riemann_zetaf; // by function-to-pointer implicit conversion
    auto &fref = std::riemann_zetal; // forming a reference
    auto mfptr = &std::allocator<int>::allocate; // forming a pointer to member function
}
(since C++20)